The Thickness of Aluminum Foil
All matter is made of atoms. A collection of only one type of atom is an
element. Aluminum is an element. One use of aluminum is to make foil,
which is used to wrap food for storage. Large numbers of aluminum atoms
are found in any sample of aluminum metal. Because each aluminum atom is
extremely small, a sample of aluminum foil is many atoms thick.
In this activity, you will calculate the size of an aluminum atom by
determining the thickness and mass of a piece of aluminum foil.
OBJECTIVES
-
Measure, indirectly, the thickness of aluminum foil.
-
Estimate the number of aluminum atoms that give the foil its
thickness.
MATERIALS
balance
metric ruler
aluminum block
100-mL graduated cylinder
piece of aluminum foil
scissors
string
PROCEDURE
-
Before you begin, form a hypothesis regarding the directly observable
data that are necessary to compute the thickness of aluminum foil.
Write your hypothesis under Data and Observations.
-
Use a balance to determine the mass of a block of aluminum metal.
Record the mass of the block in the data table.
-
Fill a 100-mL graduated cylinder with water to the 50 mL mark.
-
Tie a string to the block of aluminum and lower the block into the
water until it is completely immersed. Record the new volume of water.
-
Calculate the volume of the aluminum block by subtracting the initial
volume of water from the volume of water with the aluminum block in
it. Record in the table the volume of the aluminum block.
-
Remove the block from the cylinder, dry the block and return it to
your teacher.
-
Cut a piece of aluminum foil. The piece should be approximately 12 cm
× 12 cm. Measure the exact length and width of the foil and calculate
its area. Record the area in the table.
-
Use a balance to determine the mass of the aluminum foil. Record the
mass.
DATA AND OBSERVATIONS
Hypothesis:________________________
Mass of aluminum block
|
______g
|
Volume of water in graduated cylinder
|
______mL
|
Volume of water with aluminum block
|
______mL
|
Volume of aluminum block
|
______mL
|
Width of the piece of aluminum foil
|
______cm
|
Length of the piece of aluminum foil
|
______cm
|
Area of foil (l x w)
|
______cm2
|
Mass of aluminum foil
|
______g
|
ANALYSIS
-
What is the purpose of the block of aluminum?
-
What is the density of aluminum? (Density = Mass of aluminum
block/volume of aluminum block)
-
What is the volume of the aluminum foil? (Volume of foil = Mass of
foil/Density of aluminum)
-
What is the thickness of the foil? (Thickness of foil = Volume of
foil/Area of foil)
CONCLUSIONS
If one aluminum atom is 2.5 × 10-8cm in diameter, how
many atoms thick is the aluminum foil?
EXTENSION AND APPLICATION
Compare the diameters of magnesium, calcium, strontium, and barium
atoms. What is the relationship between the elements' atomic numbers and
the diameters of their atoms? Why do you think this is so?